3x^2-26x-50=0

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Solution for 3x^2-26x-50=0 equation:



3x^2-26x-50=0
a = 3; b = -26; c = -50;
Δ = b2-4ac
Δ = -262-4·3·(-50)
Δ = 1276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1276}=\sqrt{4*319}=\sqrt{4}*\sqrt{319}=2\sqrt{319}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{319}}{2*3}=\frac{26-2\sqrt{319}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{319}}{2*3}=\frac{26+2\sqrt{319}}{6} $

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